Answer:
The total relativistic energy of a particle is \[E=\sqrt{m_{0}^{2}{{c}^{4}}+{{p}^{2}}{{c}^{2}}}\] As wavelength \[\lambda \] is same for both electron and proton, \[\therefore \] Momentum, \[p=\frac{h}{\lambda }\] is same for both particles and hence \[{{p}^{2}}{{c}^{2}}\] is same for both. But rest mass \[{{m}_{0}}\] of a proton is greater than that of an electron, therefore, the energy of a proton is more than that of an electron of same wavelength.
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