A) 10/9
B) 11/10
C) \[{{(11/10)}^{2}}\]
D) \[{{(9/10)}^{2}}\]
Correct Answer: A
Solution :
\[n'=n\,\left( \frac{v}{v-{{v}_{S}}} \right)=n\,\left( \frac{v}{v-v/10} \right)\,\]Þ \[\frac{n'}{n}=\frac{10}{9}\]
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