JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Doppler's Effect of Light

  • question_answer
    A rocket is going away from the earth at a speed 0.2c, where c = speed of light. It emits a signal of frequency \[4\times {{10}^{7}}Hz\]. What will be the frequency observed by an observer on the earth                                            [RPMT 1996]

    A)            \[4\times {{10}^{6}}Hz\] 

    B)            \[3.2\times {{10}^{7}}Hz\]

    C)            \[3\times {{10}^{6}}Hz\] 

    D)            \[5\times {{10}^{7}}Hz\]

    Correct Answer: B

    Solution :

               \[\nu '=\nu \left( 1-\frac{v}{c} \right)=4\times {{10}^{7}}\left( 1-\frac{0.2c}{c} \right)=3.2\times {{10}^{7}}Hz\]


You need to login to perform this action.
You will be redirected in 3 sec spinner