A) 10 m along north
B) 10 m long south
C) 10 m along west
D) Zero
Correct Answer: C
Solution :
From figure, \[\overrightarrow{OA}=0\ \overrightarrow{i}+30\ \overrightarrow{j}\], \[\overrightarrow{AB}=20\ \overrightarrow{i}+0\ \overrightarrow{j}\] \[\overrightarrow{BC}=-30\sqrt{2}\ cos{{45}^{o}}\overrightarrow{i}\]\[-30\sqrt{2}\ \sin \text{4}{{\text{5}}^{\text{o}}}\overrightarrow{j}\] \[=-30\ \overrightarrow{i}-30\ \overrightarrow{j}\] \ Net displacement, \[\overrightarrow{OC}=\overrightarrow{OA}+\overrightarrow{AB}+\overrightarrow{BC}\] \[=-10\ \overrightarrow{i}+0\ \overrightarrow{j}\] \[|\overrightarrow{OC}|\ =10\ m.\]You need to login to perform this action.
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