A) \[x=A\sin (\omega \,t+\delta )\]
B) \[x=B\cos (\omega \,t+\varphi )\]
C) \[x=A\tan (\omega \,t+\varphi )\]
D) \[x=A\sin \omega \,t\cos \omega \,t\]
Correct Answer: A
Solution :
\[x=a\sin \omega \,t\cos \omega \,t=\frac{a}{2}\sin 2\omega \,t\]You need to login to perform this action.
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