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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Displacement of S.H.M. and Phase

  • question_answer
    Two equations of two S.H.M. are \[y=a\sin \,(\omega \,t-\alpha )\] and\[y=b\cos (\omega \,t-\alpha )\]. The phase difference between the two is                                                               [MP PMT 1985]

    A)            0°   

    B)            a°

    C)            90°

    D)            180°

    Correct Answer: C

    Solution :

                       \[y=a\sin (\omega \,t-\alpha )=a\cos \left( \omega \,t-\alpha -\frac{\pi }{2} \right)\] Another equation is given \[y=\cos (\omega \,t-\alpha )\] So, there exists a phase difference of \[\frac{\pi }{2}=90{}^\circ \]


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