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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Displacement of S.H.M. and Phase

  • question_answer
    The amplitude and the periodic time of a S.H.M. are 5cm and 6sec respectively. At a distance of 2.5cm away from the mean position, the phase will be

    A)            \[5\pi /12\]                           

    B)            \[\pi /4\]

    C)            \[\pi /3\]                                

    D)            \[\pi /6\]

    Correct Answer: D

    Solution :

                       Equation of motion is \[y=5\sin \frac{2\pi t}{6}\]. For \[y=2.5\,cm\] \[2.5=5\sin \frac{2\pi t}{6}\] Þ \[\frac{2\pi t}{6}=\frac{\pi }{6}\] Þ \[t=\frac{1}{2}sec\] and phase \[=\frac{2\pi t}{6}=\frac{\pi }{6}\].


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