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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Displacement of S.H.M. and Phase

  • question_answer
    Two particles are executing S.H.M. The equation of their motion are \[{{y}_{1}}=10\sin \left( \omega \,t+\frac{\pi T}{4} \right),\]\[{{y}_{2}}=25\sin \,\left( \omega \,t+\frac{\sqrt{3}\pi T}{4} \right)\]. What is the ratio of their amplitude                    [DCE 1996]

    A)            1 : 1                                          

    B)            2 : 5

    C)            1 : 2                                          

    D)            None of these

    Correct Answer: B

    Solution :

               \[\frac{{{a}_{1}}}{{{a}_{2}}}=\frac{10}{25}=\frac{2}{5}\]


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