A) \[\frac{A}{2}\]
B) \[\frac{A}{\sqrt{2}}\]
C) \[\frac{A\sqrt{3}}{2}\]
D) \[\frac{2A}{\sqrt{3}}\]
Correct Answer: C
Solution :
\[{{v}_{\max }}=\omega A\] Þ \[v=\frac{\omega A}{2}=\omega \sqrt{{{A}^{2}}-{{y}^{2}}}\] Þ \[{{A}^{2}}-{{y}^{2}}=\frac{{{A}^{2}}}{4}\] Þ \[{{y}^{2}}=\frac{3{{A}^{2}}}{4}\] Þ \[y=\frac{\sqrt{3}A}{2}\]
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