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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Displacement of S.H.M. and Phase

  • question_answer
    A particle executes a simple harmonic motion of time period T. Find the time taken by the particle to go directly from its mean position to half the amplitude            [UPSEAT 2002]

    A)            T / 2                                         

    B)            T / 4

    C)            T / 8                                         

    D)            T / 12

    Correct Answer: D

    Solution :

               \[y=A\sin \omega t\]\[=\frac{A\sin 2\pi }{T}t\] Þ \[\frac{A}{2}=A\sin \frac{2\pi t}{T}\]Þ \[t=\frac{T}{12}\].


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