A) \[y=a\sin \omega \,t\]
B) \[y=a\cos \omega \,t\]
C) \[y=a\sin \omega \,t+b\cos \omega \,t\]
D) \[y=a\tan \omega \,t\]
Correct Answer: D
Solution :
Standard equation of S.H.M. \[\frac{{{d}^{2}}y}{d{{t}^{2}}}=\,-\,{{\omega }^{2}}y,\] is not satisfied by \[y=a\tan \omega \,t\].
You need to login to perform this action.
You will be redirected in
3 sec
