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JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Displacement of S.H.M. and Phase

  • question_answer
    A \[1.00\times {{10}^{-20}}kg\] particle is vibrating with simple harmonic motion with a period of \[1.00\times {{10}^{-5}}sec\] and a maximum speed of \[1.00\times {{10}^{3}}m/s\]. The maximum displacement of the particle is                                                                  [AMU (Med.) 1999]

    A)            1.59 mm                                 

    B)            1.00 m

    C)            10 m                                        

    D)            None of these

    Correct Answer: A

    Solution :

                       \[{{v}_{\max }}=a\omega =a\times \frac{2\pi }{T}\] Þ \[a=\frac{{{v}_{\max }}\times T}{2\pi }\]            \[A=\frac{1.00\times {{10}^{3}}\times (1\times {{10}^{-5}})}{2\pi }=1.59\]mm


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