A) Maximum velocity
B) Maximum acceleration
C) Maximum energy
D) Maximum displacement
Correct Answer: D
Solution :
For S.H.M. displacement \[y=a\sin \omega \,t\] and acceleration \[A=\,-{{\omega }^{2}}y\sin \omega \,t\] these are maximum at \[\omega \,t=\frac{\pi }{2}.\]
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