A) 12 days
B) 13 days
C) \[13\frac{5}{7}\]days
D) \[13\frac{3}{4}\]days
Correct Answer: D
Solution :
(d): This is exactly like Q11. Here, it will be\[\frac{1}{16}+\frac{1}{12}=\frac{3+4}{48}=\frac{7}{48}\]. \[\Rightarrow \]In 12 days \[\left( 6\times 2days \right),\frac{7\times 6}{48}=\frac{42}{48}\]work gets done. \[\Rightarrow \frac{6}{48}or\frac{1}{8}\]work is left. On 13th day, A finishes another\[\frac{1}{16}\]work. \[\Rightarrow \frac{1}{8}-\frac{1}{16}=\frac{1}{16}\]part work is left Now its ?B's turn on 14th day beginning To complete \[\frac{1}{16}\] work, he takes 1 day \[\therefore \]to complete \[\frac{1}{16}\]work, he will take \[\frac{1\times 12}{16}\]day \[=\frac{3}{4}\]day. \[\therefore \]total days \[=13\frac{3}{4}\].
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