A) 3
B) 4
C) 2
D) 6
Correct Answer: B
Solution :
As \[x\] and \[y\] vary inversely \[\therefore xy=\] constant or \[{{x}_{1}}{{y}_{1}}={{x}_{2}}{{y}_{2}}\] \[\Rightarrow 10\times 6=15{{y}_{2}}(\because {{x}_{1}}=10,{{y}_{1}}=6,{{x}_{2}}=15)\] \[\Rightarrow {{y}_{2}}=\frac{10\times 6}{15}=4\]You need to login to perform this action.
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