question_answer

Let \[[{{\varepsilon }_{0}}]\] denotes the dimensional formula of the permittivity of the vacuum and \[[{{\mu }_{0}}]\] that of the permeability of the vacuum. If \[M=\text{mass}\], \[L=\text{length}\], \[T=\text{Time}\] and \[I=\text{electric current}\], then                                 [IIT 1998]

A)             \[[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{2}}I\]           

B)             \[[{{\varepsilon }_{0}}]={{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{I}^{2}}\]

C)             \[[{{\mu }_{0}}]=ML{{T}^{-2}}{{I}^{-2}}\]   

D)             \[[{{\mu }_{0}}]=M{{L}^{2}}{{T}^{-1}}I\]