A) \[L{{T}^{-1}}\]
B) \[{{L}^{-2}}{{T}^{2}}\]
C) \[{{M}^{-1}}{{L}^{-3}}{{Q}^{2}}{{T}^{2}}\]
D) \[{{M}^{-1}}{{L}^{-3}}{{I}^{2}}{{T}^{2}}\]
Correct Answer: B
Solution :
\[C=\frac{1}{\sqrt{{{\mu }_{0}}{{\varepsilon }_{0}}}}\]Þ\[{{\mu }_{0}}{{\varepsilon }_{0}}=\left( \frac{1}{{{C}^{2}}} \right)\](where C = velocity of light) \ \[[{{\mu }_{0}}{{\varepsilon }_{0}}]={{L}^{-2}}{{T}^{2}}\]
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