A) Energy per unit volume
B) Force per unit area
C) Product of voltage and charge per unit volume
D) Angular momentum per unit mass
Correct Answer: D
Solution :
Energy per unit volume = \[\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{L}^{3}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Force per unit area = \[\frac{[ML{{T}^{-2}}]}{[{{L}^{2}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Product of voltage and charge per unit volume \[=\frac{V\times Q}{\text{Volume}}=\frac{VIt}{\text{Volume}}=\frac{\text{Power}\times \text{Time}}{\text{Volume}}\] \[\Rightarrow \] \[\frac{[M{{L}^{2}}{{T}^{-3}}]\,[T]}{[{{L}^{3}}]}=[M{{L}^{-1}}{{T}^{-2}}]\] Angular momentum per unit mass = \[\frac{[M{{L}^{2}}{{T}^{-1}}]}{[M]}=[{{L}^{2}}{{T}^{-1}}]\] So angular momentum per unit mass has different dimension.
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