NEET Physics Mathematical Tools, Units & Dimensions Question Bank Dimensions

  • question_answer
    The dimensional formula for Planck's constant \[(h)\] is          [DPMT 1987; MP PMT 1983, 96; IIT 1985; MPPET 1995; AFMC 2003; RPMT 1999; Kerala PMT 2002]

    A)             \[M{{L}^{-2}}{{T}^{-3}}\]         

    B)             \[M{{L}^{2}}{{T}^{-2}}\]

    C)             \[M{{L}^{2}}{{T}^{-1}}\]

    D)     \[M{{L}^{-2}}{{T}^{-2}}\]

    Correct Answer: C

    Solution :

        \[E=hv\Rightarrow [M{{L}^{2}}{{T}^{-2}}]=[h]\,[{{T}^{-1}}]\Rightarrow [h]=[M{{L}^{2}}{{T}^{-1}}]\]  


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