A) 0.625
B) 0.0625
C) 0.00625
D) 625
Correct Answer: D
Solution :
CGS SI \[{{N}_{1}}{{U}_{1}}={{N}_{2}}{{U}_{2}}\] \[{{N}_{1}}\left[ {{M}_{1}}L_{1}^{-3} \right]={{N}_{2}}\left[ {{M}_{2}}L_{2}^{-3} \right]\] \[\therefore \] \[{{N}_{2}}={{N}_{1}}\left[ \frac{{{M}_{1}}}{{{M}_{2}}} \right]\times {{\left[ \frac{{{L}_{1}}}{{{L}_{2}}} \right]}^{-3}}\] \[=0.625\left[ \frac{1g}{1kg} \right]\times {{\left[ \frac{1cm}{1m} \right]}^{-3}}\] \[=0.625\times {{10}^{-3}}\times {{10}^{6}}=625\]
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