A) \[[{{M}^{0}}{{L}^{-1}}{{T}^{-1}}]\]
B) \[[{{M}^{0}}L{{T}^{-1}}]\]
C) \[[{{M}^{0}}{{L}^{-1}}{{T}^{0}}]\]
D) \[[{{M}^{0}}LT]\]
Correct Answer: C
Solution :
\[[Kx]\]= Dimension of \[\omega t=\](dimensionless) hence \[K=\frac{1}{X}=\frac{1}{L}=\left[ {{L}^{-1}} \right]\] \ \[[K]=[{{L}^{-1}}]\]
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