A) \[k{{\rho }^{1/2}}{{a}^{3/2}}\mathbf{/}\sqrt{T}\]
B) \[k{{\rho }^{3/2}}{{a}^{3/2}}/\sqrt{T}\]
C) \[k{{\rho }^{1/2}}{{a}^{3/2}}/{{T}^{3/4}}\]
D) \[k{{\rho }^{1/2}}{{a}^{1/2}}/{{T}^{3/2}}\]
Correct Answer: A
Solution :
Let \[n=k{{\rho }^{a}}{{a}^{b}}{{T}^{c}}\] where \[[\rho ]=[M{{L}^{-3}}],\ [a]=[L]\] and \[[T]=[M{{T}^{-2}}]\] Comparing both sides, we get\[a=\frac{1}{2},\,b=\frac{3}{2}\] and \[c=\frac{-1}{2}\] \ \[\eta =\frac{k{{\rho }^{1/2}}{{a}^{3/2}}}{\sqrt{T}}\]
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