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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    A single slit of width 0.20 mm is illuminated with light of wavelength 500 nm. The observing screen is placed 80 cm from the slit. The width of the central bright fringe will be   [AMU (Med.) 2002]

    A)            1 mm                                       

    B)            2 mm 

    C)            4 mm                                       

    D)            5 mm

    Correct Answer: C

    Solution :

                       Width of central bright fringe.            \[=\frac{2\lambda D}{d}=\frac{2\times 500\times {{10}^{-9}}\times 80\times {{10}^{-2}}}{0.20\times {{10}^{-3}}}\]\[=4\times {{10}^{-3}}m=4mm.\]


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