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JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Diffraction of Light

  • question_answer
    A light wave is incident normally over a slit of width\[24\times {{10}^{-5}}cm\]. The angular position of second dark fringe from the central maxima is 30o. What is the wavelength of light                                                 [RPET 1995]

    A) \[6000\,\,{AA}\]               

    B) \[5000\,\,{AA}\]

    C) \[3000\,\,{AA}\]               

    D) \[1500\,\,{AA}\]

    Correct Answer: A

    Solution :

    For second dark fringe \[d\sin \theta =2\lambda \]                    \[\Rightarrow \] \[24\times {{10}^{-5}}\times {{10}^{-2}}\times \sin 30=2\lambda \]            \[\Rightarrow \] \[\lambda =6\times {{10}^{-7}}\,m\,\,=\,\,6000\,{AA}\]


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