A) \[9\,m\]
B) \[12\,m\]
C) \[24\,m\]
D) \[36\,m\]
Correct Answer: A
Solution :
\[{{f}_{1}}=\frac{{{r}^{2}}}{\lambda }=\frac{{{(2.3\times {{10}^{-3}})}^{2}}}{5893\times {{10}^{-10}}}=9\,m.\]
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