A) \[{V}'=2V\]
B) \[{V}'>2V\]
C) \[{V}'>>2V\]
D) \[V'<2V\]
Correct Answer: D
Solution :
For conversion of galvanometer (of resistances) into voltmeter, a resistance R is connected in series. \ \[{{i}_{g}}=\frac{{{V}_{1}}}{R+G}\] and \[{{i}_{g}}=\frac{{{V}_{2}}}{2R+G}\] Þ \[\frac{{{V}_{1}}}{R+G}=\frac{{{V}_{2}}}{2R+G}\] Þ \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{2R+G}{R+G}=\frac{2(R+G)-G}{(R+G)}\] \[=2-\frac{G}{(R+G)}\]Þ \[{{V}_{2}}=2{{V}_{1}}-\frac{{{V}_{1}}G}{(R+G)}\]Þ \[{{V}_{2}}<2{{V}_{1}}\]
You need to login to perform this action.
You will be redirected in
3 sec
