2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर

JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    In a potentiometer experiment two cells of e.m.f. E1 and E2 are used in series and in conjunction and the balancing length is found to be 58 cm of the wire.  If the polarity of E2 is reversed, then the balancing length becomes 29 cm.  The ratio \[\frac{{{E}_{1}}}{{{E}_{2}}}\] of the e.m.f. of the two cells is                                                                                   [Kerala (Engg.) 2001]

    A)         1 : 1                                  

    B)         2 : 1

    C)         3 : 1                                  

    D)         4 : 1

    Correct Answer: C

    Solution :

                                             \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{l}_{1}}+{{l}_{2}}}{{{l}_{1}}-{{l}_{2}}}=\frac{58+29}{58-29}=\frac{3}{1}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner