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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    AB is a potentiometer wire of length 100 cm and its resistance is 10 ohms.  It is connected in series with a resistance R = 40 ohms and a battery of e.m.f. 2 V and negligible internal resistance.  If a source of unknown e.m.f. E is balanced by 40 cm length of the potentiometer wire, the value of E is                                              [MP PET 2001]

    A)            0.8 V

    B)                    1.6 V

    C)         0.08 V

    D)         0.16 V

    Correct Answer: D

    Solution :

                                             \[E=\frac{e}{(R+{{R}_{h}}+r)}\,\frac{R}{L}\times l\]\[=\frac{2}{(10+40+0)}\times \frac{10}{1}\times 0.4=0.16V\].


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