JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    Voltmeters V1 and V2 are connected in series across a D.C. line.  V1 reads 80 volts and has a per volt resistance of 200 ohms.  V2 has a total resistance of 32 kilo ohms.  The line voltage is                                           [UPSEAT 2000]

    A)         120 volts

    B)         160 volts

    C)         220 volts                         

    D)         240 volts

    Correct Answer: D

    Solution :

                                             \[{{R}_{1}}=80\times 200=16000\,\Omega =16\,k\Omega \] Current flowing through \[{{V}_{1}}\]= Current flowing through \[{{V}_{2}}\] = \[\frac{80}{16\times {{10}^{3}}}=5\times {{10}^{-3}}A\]. So, potential differences across \[{{V}_{2}}\] is \[{{V}_{2}}=5\times {{10}^{-3}}\times 32\times {{10}^{3}}=160\,\text{volt}\] Hence, line voltage \[V={{V}_{1}}+{{V}_{2}}=80+160=240V\].


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