JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    A galvanometer of 25 W resistance can read a maximum current of 6mA.  It can be used as a voltmeter to measure a maximum of 6 V by connecting a resistance to the galvanometer.  Identify the correct choice in the given answers                                                                       [EAMCET (Med.) 2000]

    A)         1025 W in series          

    B)         1025 W in parallel

    C)         975 W in series             

    D)         975 W in parallel

    Correct Answer: C

    Solution :

                                             \[R=\frac{V}{{{i}_{g}}}-G=\frac{6}{6\times {{10}^{-3}}}-25=975\Omega \](In series).


You need to login to perform this action.
You will be redirected in 3 sec spinner