JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    In the given figure, battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10 W is connected in parallel with the battery then it balances on 50 cm length of the potentiometer wire then internal resistance r of the battery is             [DCE 2000; RPET 2000]

    A)         1 W

    B)         3 W

    C)         10 W

    D)         5 W

    Correct Answer: A

    Solution :

                                             \[r=\left( \frac{{{l}_{1}}-{{l}_{2}}}{{{l}_{2}}} \right)\times R'\]\[\Rightarrow r=\left( \frac{55-50}{50} \right)\times 10=1\Omega \].


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