A) 1 : 9
B) 1 : 10
C) 1 : 11
D) 9 : 1
Correct Answer: D
Solution :
\[S=\frac{{{i}_{g}}G}{(i-{{i}_{g}})}\] Þ \[\frac{G}{S}=\frac{i-{{i}_{g}}}{{{i}_{g}}}=\frac{10-1}{1}=\frac{9}{1}\]
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