2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर

JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    A potentiometer wire of length \[1\,m\] and resistance 10 W is connected in series with a cell of emf 2V with internal resistance 1 W and a resistance box including a resistance R.  If potential difference between the ends of the wire is 1 mV, the value of R is                                                      [KCET 1999]

    A)         20000 W

    B)                        19989 W

    C)         10000 W                          

    D)         9989 W

    Correct Answer: B

    Solution :

                                             \[V=i.R\text{. }=\frac{e}{(R+{{R}_{h}}+r)}\,.\,R\Rightarrow {{10}^{-3}}=\frac{2}{(10+R+r)}\times 10\] \[\Rightarrow R=19,989\Omega \].


You need to login to perform this action.
You will be redirected in 3 sec spinner