A) 0.80 volt
B) 1.60 volt
C) 1.33 volt
D) 2.00 volt
Correct Answer: C
Solution :
Total resistance of the circuit \[=\frac{80}{2}+20=60\,\Omega \] Þ Main current \[i=\frac{2}{60}=\frac{1}{30}A\] Combination of voltmeter and 80W resistance is connected in series with 20W, so current through 20W and this combination will be same \[=\frac{1}{30}A\]. Since the resistance of voltmeter is also 80W, so this current is equally distributed in 80W resistance and voltmeter (i.e.\[\frac{1}{60}A\]through each) P.D. across 80W resistance \[=\frac{1}{60}\times 80=1.33\,V\]
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