JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    \[50\,\Omega \] and \[100\,\Omega \] resistors are connected in series. This connection is connected with a battery of 2.4 volts. When a voltmeter of \[100\,\Omega \] resistance is connected across \[100\,\Omega \] resistor, then the reading of the voltmeter will be                                                                                           [MP PMT 1985]

    A)                    1.6 V

    B)                                      1.0 V

    C)                    1.2 V

    D)            2.0 V

    Correct Answer: C

    Solution :

                 Equivalent resistance of the circuit \[{{R}_{eq}}=100\Omega \] current through the circuit \[i=\frac{2.4}{100}A\] P.D. across combination of voltmeter and 100 W resistance \[=\frac{2.4}{100}\times 50=1.2V\] Since the voltmeter and 100 W resistance are in parallel, so the voltmeter reads the same value i.e. 1.2V.             


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