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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    . The resistivity of a potentiometer wire is \[40\times {{10}^{-8}}\,ohm-m\] and its area of cross-section is \[8\times {{10}^{-6}}\,{{m}^{2}}\]. If 0.2 amp current is flowing through the wire, the potential gradient will be                                         [MP PMT/PET 1998]

    A)                    \[{{10}^{-2}}\,volt/m\]

    B)                                      \[{{10}^{-1}}\,volt/m\]

    C)                    \[3.2\times {{10}^{-2}}\,volt/m\]                            

    D)            \[1\,volt/m\]

    Correct Answer: A

    Solution :

                 Potential gradient\[=\frac{V}{L}=\frac{iR}{L}=\frac{i\rho L}{AL}=\frac{i\rho }{A}\]            \[=\frac{0.2\times 40\times {{10}^{-8}}}{8\times {{10}^{-6}}}={{10}^{-2}}\,V/m\]


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