JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    A resistance of \[4\,\Omega \] and a wire of length 5 metres and resistance \[5\,\Omega \] are joined in series and connected to a cell of e.m.f. 10 V and internal resistance \[1\,\Omega \]. A parallel combination of two identical cells is balanced across 300 cm of the wire.  The e.m.f. E of each cell is              [MP PMT 1997]           

    A)                                                      1.5 V

    B)                    3.0 V

    C)                    0.67 V

    D)                    1.33 V

    Correct Answer: B

    Solution :

                 \[E=x\,l=\frac{V}{l}=\frac{iR}{L}\times l\]Þ \[E=\frac{e}{(R+{{R}_{h}}+r)}\times \frac{R}{L}\times l\]            Þ\[E=\frac{10}{(5+4+1)}\times \frac{5}{5}\times 3=3\,V\]


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