JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    The resistance of a galvanometer is 50 ohms and the current required to give full scale deflection is \[100\,\mu A\]. In order to convert it into an ammeter, reading upto 10A, it is necessary to put a resistance of         [MP PMT 1997; AIIMS 1999]

    A)                    \[5\times {{10}^{-3}}\,\Omega \] in parallel       

    B)            \[5\times {{10}^{-4}}\,\Omega \] in parallel

    C)                    \[{{10}^{5}}\,\Omega \] in series                            

    D)            \[99,950\,\Omega \]in series

    Correct Answer: B

    Solution :

                 Resistance in parallel \[S=\frac{G{{i}_{g}}}{i-{{i}_{g}}}=\frac{50\times 100\times {{10}^{-6}}}{(10-100\times {{10}^{-6}})}\]            Þ \[S=5\times {{10}^{-4}}\,\Omega \]


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