JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    In the Wheatstone's bridge (shown in figure) \[X=Y\] and \[A>B\]. The direction of the current between ab will be

    A)            From a to b

    B)                    From b to a

    C)                    From b to a through c

    D)                    From a to b through c

    Correct Answer: B

    Solution :

                 In the part c b d, \[{{V}_{c}}-{{V}_{b}}={{V}_{b}}-{{V}_{d}}\] Þ \[{{V}_{b}}=\frac{{{V}_{c}}+{{V}_{d}}}{2}\]                    In the part c a d            \[{{V}_{c}}-{{V}_{a}}>{{V}_{a}}-{{V}_{d}}\] Þ \[\frac{{{V}_{c}}+{{V}_{d}}}{2}>{{V}_{a}}\] Þ \[{{V}_{b}}>{{V}_{a}}\]


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