question_answer

The circuit shown here is used to compare the e.m.f. of two cells \[{{E}_{1}}\] and \[{{E}_{2}}({{E}_{1}}>{{E}_{2}})\]. The null point is at C when the galvanometer is connected to \[{{E}_{1}}\]. When the galvanometer is connected to \[{{E}_{2}}\], the null point will be  [MP PMT 1995]

A)                    To the left of C

B)                    To the right of C

C)                    At C itself

D)                    Nowhere on AB