A) \[2.5\times {{10}^{-4}}ohm\]
B) \[1.25\times {{10}^{-3}}ohm\]
C) 0.05 ohm
D) 2.5 ohm
Correct Answer: A
Solution :
\[S=\frac{G}{\frac{i}{{{i}_{g}}}-1}=\frac{25}{\frac{5}{50\times {{10}^{-6}}}-1}\] \[=\frac{25}{{{10}^{5}}-1}=\frac{25}{{{10}^{5}}}=2.5\times {{10}^{-4}}\Omega \]
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