JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    The current flowing through a coil of resistance 900 ohms is to be reduced by 90%. What value of shunt should be connected across the coil                                      [Roorkee 1992]

    A)                    \[90\,\Omega \]

    B)                                      \[100\,\Omega \]

    C)                    \[9\,\Omega \]            

    D)            \[10\,\Omega \]

    Correct Answer: B

    Solution :

                 Q \[{{i}_{g}}=(100-90)%\] of \[i=\frac{i}{10}\] Þ Required shunt \[S=\frac{G}{(n-1)}=\frac{900}{(10-1)}=100\,\Omega \]


You need to login to perform this action.
You will be redirected in 3 sec spinner