A) \[50/99\,\Omega \] in series
B) \[50/99\,\Omega \] in parallel
C) \[0.01\,\Omega \] in series
D) \[0.01\,\Omega \] in parallel
Correct Answer: B
Solution :
\[S=\frac{{{i}_{g}}\times G}{i-{{i}_{g}}}=\frac{10\times {{10}^{-3}}\times 50}{1-{{10}^{-3}}\times 10}=\frac{50}{99}\Omega \] in parallel.
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