A) 10 ohms in series
B) 10 ohms in parallel
C) 810 ohms in series
D) 810 ohms in parallel
Correct Answer: B
Solution :
Q \[{{i}_{g}}=10%\] of \[i=\frac{i}{10}\]Þ \[S=\frac{G}{(n-1)}=\frac{90}{(10-1)}=10\Omega \]
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