A) \[\frac{10}{999}\]ohm
B) 0.1 ohm
C) 0.5 ohm
D) 1.0 ohm
Correct Answer: A
Solution :
\[S=\frac{{{i}_{g}}G}{i-{{i}_{g}}}=\frac{10\times 0.01}{10-0.01}=\frac{10}{999}ohm\]
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