A) 1 V
B) 1.5 V
C) 2 V
D) 3 V
Correct Answer: A
Solution :
Here same current is passing throughout the length of the wire, hence \[V\propto R\propto l\] Þ \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{l}_{1}}}{{{l}_{2}}}\] Þ \[\frac{6}{{{V}_{2}}}=\frac{300}{50}\] Þ V2 =1 V.
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