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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    Two resistances are connected in two gaps of a metre bridge. The balance point is 20 cm from the zero end. A resistance of 15 ohms is connected in series with the smaller of the two. The null point shifts to 40 cm. The value of the smaller resistance in ohms is                                                     [KCET 2005]

    A)         3                                        

    B)         6

    C)         9                                        

    D)         12

    Correct Answer: C

    Solution :

                                             Let S be larger and R be smaller resistance connected in two gaps of meter bridge.                    \ \[S=\left( \frac{100-l}{l} \right)R=\frac{100-20}{20}R=4R\]   .....(i)                    When \[15\Omega \] resistance is added to resistance R, then                    \[S=\left( \frac{100-40}{40} \right)(R+15)=\frac{6}{4}(R+15)\]      .... (ii) From equations (i) and (ii) \[R=9\Omega \]


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