A) 1.1 V
B) 1.8 V
C) 2.4 V
D) 1.41 V
Correct Answer: D
Solution :
\[E=\frac{V}{l}\]; E is constant (volt. gradient). Þ \[\frac{{{V}_{1}}}{{{l}_{1}}}=\frac{{{V}_{2}}}{{{l}_{2}}}\] Þ \[\frac{1.1}{140}=\frac{V}{180}\]Þ \[V=\frac{180\times 1.1}{140}=1.41\,V\]
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