A) 2500 W as a shunt
B) 2450 W as a shunt
C) 2550 W in series
D) 2450 W in series
Correct Answer: D
Solution :
Full deflection current \[{{i}_{g}}=25\times 4\times {{10}^{-4}}\] \[=100\times {{10}^{-4}}A\] Using \[R=\frac{V}{{{I}_{g}}}-G\]\[=\frac{25}{100\times {{10}^{-4}}}-50\]\[=2450\,\Omega \]in series.
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