JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Different Measuring Instruments

  • question_answer
    An ammeter of 5 ohm resistance can read 5 mA. If it is to be used to read 100 volts, how much resistance is to be connected in series                                           [MP PET 1991; MP PMT 1996; MP PMT 2000]

    A)                    \[19.9995\,\Omega \]      

    B)            \[199.995\Omega \]

    C)                    \[1999.95\,\Omega \]      

    D)            \[19995\,\Omega \]

    Correct Answer: C

    Solution :

                 By using \[R=\frac{V}{{{I}_{g}}}-G\] Þ \[R=\frac{100}{5\times {{10}^{-3}}}-5=19,995\Omega \]


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